taklif 6

‫ﺩﺍﻧﺸﮕﺎﻩ ﺻﻨﻌﺘﻲ ﺍﺻﻔﻬﺎﻥ‬

‫ﺩﺍﻧﺸﻜﺪﻩ ﻣﻬﻨﺪﺳﻲ ﻋﻤﺮﺍﻥ‬

‫ﺑﺴﻤﻪ ﺗﻌﺎﻟﻲ‬

‫ﺣﻞ ﺗﻤﺮﻳﻦ ﻧﻘﺸﻪ ﺑﺮداري )ﺟﻌﻔﺮي ‪ -‬ﺣﺴﻴﻨﻲ(‬

‫‪ -١‬ﺑﺎ ﺗﻮﺟﻪ ﺑﻪ ﺟﺪﻭﻝ ﺯﻳﺮ ﻣﻄﻠﻮﺑﺴﺖ ﻣﺤﺎﺳﺒﻪ ﻱ ﺯﺍﻭﻳﻪ‪ ACD‬؟‬ ‫ﺍﻳﺴﺘﮕﺎﻩ‬ ‫‪A‬‬

‫‪B‬‬

‫ﻧﺸﺎﻧﻪ‬

‫ﺯﺍﻭﻳﻪ ﺍﻓﻘﻲ )ﭼﭗ(‬

‫ﺯﺍﻭﻳﻪ ﺍﻓﻘﻲ )ﺭﺍﺳﺖ(‬

‫‪C‬‬

‫˝‪٣٤٥° ١٠´ ٣٠‬‬

‫˝‪١٦٥° ١٠´ ٢٠‬‬

‫‪D‬‬

‫˝‪٢٠° ١٨´ ٥‬‬

‫˝‪٢٠٠° ١٧´ ٥٥‬‬

‫‪B‬‬

‫˝‪٦٠° ٨´ ٢٠‬‬

‫˝‪٢٤٠° ٨´ ٤٠‬‬

‫‪A‬‬

‫˝‪٣٠٠° ٣٢´ ١٥‬‬

‫˝‪١٢٠° ٣٢´ ٢٥‬‬

‫‪C‬‬

‫˝‪٣٥٠° ٢٨´ ١٠‬‬

‫‪D‬‬

‫˝‪١٧٠° ٢٧´ ٥٠‬‬ ‫˝‪٢٠٠° ٤٢´ ٤٠‬‬

‫˝‪٢٠° ٤٢´ ٣٠‬‬

‫‪...................................................................................................................................................................................................................................................................‬‬

‫‪ -١‬ﺑﻪ ﻭﺳﻴﻠﻪ ﻳﻚ ﺩﺳﺘﮕﺎﻩ ﺗﺮﺍﺯ ﻳﺎﺏ ﻛﻪ ﻭﺳﻂ ﻳﻚ ﺯﻣﻴﻦ ﭼﻬﺎﺭ ﺿﻠﻌﻲ ﺩﺭ ﻣﻜﺎﻥ ﻣﻨﺎﺳﺒﻲ ﻭﺍﻗﻊ ﺷﺪﻩ‪ ،‬ﺯﻣﻴﻦ ﺭﺍ ﺑﻪ‬ ‫ﺻﻮﺭﺕ ﺯﻳﺮ ﺑﺮﺩﺍﺷﺖ ﻣﻲ ﻛﻨﻴﻢ‪.‬ﻣﻄﻠﻮﺏ ﺍﺳﺖ ‪:‬‬ ‫ﺏ‪ -‬ﻃﻮﻝ ﻭ ﺷﻴﺐ ﺍﺯ ‪ A‬ﺑﻪ ‪ D‬ﺑﻪ ﺩﺭﺻﺪ‬

‫ﺍﻟﻒ‪ -‬ﻣﺴﺎﺣﺖ ﺯﻣﻴﻦ‬

‫‪D =١٠٠(U – L) cos٢α‬‬

‫‪∆h =١٠٠ (U – L) sinαcosα + hi –M‬‬ ‫ﺍﻳﺴﺘﮕﺎﻩ‬ ‫‪S‬‬

‫ﻧﻘﻄﻪ ﻧﺸﺎﻧﻪ‬

‫ﺗﺎﺭ ﺑﺎﻻ‬

‫ﺗﺎﺭ ﻭﺳﻂ‬

‫ﺗﺎﺭﭘﺎﺋﻴﻦ‬

‫ﻟﻤﺐ ﺍﻓﻘﻲ‬

‫‪A‬‬

‫‪١٧٨٠‬‬

‫‪٨٢٠‬‬

‫‪-‬‬

‫´‪١٥٨˚٣٠‬‬

‫‪B‬‬

‫‪٣٣٢٠‬‬

‫‪٢٥٨٠‬‬

‫‪١٨٤٠‬‬

‫´‪٢٥٦˚١٤‬‬

‫‪C‬‬

‫‪٢٩٩٠‬‬

‫‪٢٣٢٠‬‬

‫‪١٦٥٠‬‬

‫´‪٢٩٨˚٣٣‬‬

‫‪D‬‬

‫‪-‬‬

‫‪٣٦٥٠‬‬

‫‪٢٨٣٠‬‬

‫´‪٣٣˚١٢‬‬

‫‪.....................................................................................................................................................................................................................................................................‬‬

‫‪-٣‬ﻗﺮﺍﺋﺖ ﻫﺎﻱ ﺯﻳﺮ ﺗﻮﺳﻂ ﻳﻚ ﺩﺳﺘﮕﺎﻩ ﺗﺮﺍﺯﻳﺎﺏ ﺑﺮ ﺭﻭﻱﻧﻘﺎﻁ ‪ A‬ﻭ ‪ B‬ﺍﻧﺠﺎﻡ ﺷﺪﻩ ﺍﺳﺖ‪ .‬ﻣﻄﻠﻮﺑﺴﺖ ﺷﻴﺐ ‪.AB‬‬ ‫ﻧﺸﺎﻧﻪ‬

‫ﺗﺎﺭ ﺑﺎﻻ‬

‫ﺗﺎﺭ ﻭﺳﻂ‬

‫ﺗﺎﺭ ﭘﺎﻳﻴﻦ‬

‫ﻟﻤﺐ ﺍﻓﻘﻲ‬

‫‪A‬‬

‫‪٣١٥٢‬‬

‫‪٢٧١٨‬‬

‫‪٢٢٨٦‬‬

‫‪٢٧٥.٢٥g‬‬

‫‪B‬‬

‫‪٢٨١٢‬‬

‫‪٢١٣٠‬‬

‫‪١٤٥٠‬‬

‫‪٣٤٢.٥٥g‬‬

‫‪hi =١.٦ m‬‬

‫ﻣﻮﻓﻖ ﺑﺎﺷﻴﺪ‬ ‫ﺣﺴﻴﻨﯽ‬